<?xml version='1.0' encoding='UTF-8'?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/'><id>tag:blogger.com,1999:blog-23073148</id><updated>2008-04-05T17:06:24.853+11:00</updated><title type='text'>onlinetutor.com.au</title><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/'/><link rel='next' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default?start-index=26&amp;max-results=25'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default'/><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml'/><author><name>Amanda &amp; Debbie</name></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>29</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-23073148.post-1141333929123135892</id><published>2006-11-23T12:04:00.000+11:00</published><updated>2006-11-23T12:11:51.933+11:00</updated><title type='text'>Prime and Composite Number Worksheet</title><summary type='text'>
Classify each of the following numbers as prime, composite or neither.

a) 28

b) 13

c) 171

d) 45

e) 2

f) 33

g) 240

h) 97

i) 5

j) 67

k) 0

l) 193


Answers

a) Composite

b) Prime

c) Composite

d) Composite

e) Prime

f) Composite

g) Composite

h) Prime

i) Prime

j) Prime

k) Neither prime nor composite

l) Prime</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/11/prime-and-composite-number-worksheet.html' title='Prime and Composite Number Worksheet'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=1141333929123135892' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/1141333929123135892'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/1141333929123135892'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-8850391700178380821</id><published>2006-11-15T21:33:00.000+11:00</published><updated>2006-11-15T21:38:54.396+11:00</updated><title type='text'>Practise Simplifying Fractions</title><summary type='text'>
Write each of the following fractions in their lowest equivalent form (simplest form).

1) 57/159

2) 396/770

3) 322/1372

4) 58/435

5) 52/100

6) 2/26

7) 32/48

8) 17/85

9) 34/102

10) 27/36

11) 56/21

12) 350/45



Answers

1) 19/53
2) 18/35
3) 23/98
4) 2/15
5) 13/25
6) 1/13
7) 2/3
8) 1/5
9) 1/3
10) 3/4
11) 8/3
12) 70/9 </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/11/practise-simplifying-fractions.html' title='Practise Simplifying Fractions'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=8850391700178380821' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/8850391700178380821'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/8850391700178380821'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-2255009798479709037</id><published>2006-11-15T10:55:00.000+11:00</published><updated>2006-11-15T10:56:01.658+11:00</updated><title type='text'>Greatest Common Factor Practise Questions</title><summary type='text'>
What is the greatest common factor of

1) 57 and 159

2) 396 and 770

3) 1372 and 322

4) 435 and 58

5) 52 and 100

6) 26 and 2

7) 32 and 48

8) 85 and 17

9) 34 and 102

10) 27 and 36

11) 21 and 56

12) 45 and 350

13) 10, 50 and 130

14) 16, 64 and 36


Answers
1) 3
2) 22
3) 14
4) 29
5) 4
6) 2
7) 16
8) 17
9) 34
10) 9
11) 7
12) 5
13) 10
14) 4 </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/11/greatest-common-factor-practise.html' title='Greatest Common Factor Practise Questions'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=2255009798479709037' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/2255009798479709037'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/2255009798479709037'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-1460340934071940184</id><published>2006-11-14T11:40:00.000+11:00</published><updated>2006-11-14T11:41:27.025+11:00</updated><title type='text'>Least Common Multiple (LCM) Practise Questions</title><summary type='text'>
What is the least common multiple (lowest common multiple) of

1) 15 and 60

2) 12 and 210

3) 9 and 14

4) 55 and 22

5) 4 and 98

6) 9 and 8

7) 9, 10 and 30

8) 2, 16, 14 and 56


Answers

1) 60

2) 420

3) 126

4) 110

5) 196

6) 72

7) 90

8) 112 </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/11/least-common-multiple-lcm-practise.html' title='Least Common Multiple (LCM) Practise Questions'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=1460340934071940184' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/1460340934071940184'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/1460340934071940184'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-6323738183735322197</id><published>2006-11-14T10:32:00.000+11:00</published><updated>2006-11-14T11:39:59.538+11:00</updated><title type='text'>Practise Questions: Arithmetic and Geometric Sequences</title><summary type='text'>
Answer the following questions for each of the sequences below.

a) Is it an arithmetic sequence, a geometric sequence, or neither?
b) If it is an arithmetic sequence, what is the common difference? If it is a geometric sequence, what is the common ratio?
c) If it is an arithmetic or geometric sequence, what are the next three terms in the sequence?

1) 128, 64, 32, 16, 8, ...

2) -8, 4, 16, 28,</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/11/practice-questions-arithmetic-and.html' title='Practise Questions: Arithmetic and Geometric Sequences'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=6323738183735322197' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/6323738183735322197'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/6323738183735322197'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-116302896494935474</id><published>2006-11-09T10:13:00.000+11:00</published><updated>2006-11-09T12:28:20.885+11:00</updated><title type='text'>Practise Fraction Questions Year 7 &amp; 8</title><summary type='text'>
Solve the following:

1) 3/11 divided by 66/9. Write the answer in simplest form.

2) 3/4 divided by 2/6. Write the answer as a mixed number.

3) 3/4 + 15/98. Write the answer in simplest form.

4) 7/9 - 1/8. Write the answer in simplest form.

5) 6 6/16 + 8 3/12. Write the answer as a mixed number.

6) -5/6 + 8/22. Write the answer in simplest form.

7) 2/17 x 3/6. Write the answer in simplest </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/11/practise-fraction-questions-year-7-8.html' title='Practise Fraction Questions Year 7 &amp; 8'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=116302896494935474' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/116302896494935474'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/116302896494935474'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-116155934505940188</id><published>2006-10-23T09:16:00.000+10:00</published><updated>2006-11-09T12:28:20.747+11:00</updated><title type='text'>What Is The Greatest Common Factor (GCF) Of 60 And 72?</title><summary type='text'>
We are trying to find the largest (or greatest) number that is a factor of both 60 and 72.

You could use either of the following methods to find the greatest common factor.

Method 1.

List all of the factors of each number.

The factors of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.

The factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72.

1, 2, 3, 4, 6 and 12 are the factors </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/10/what-is-greatest-common-factor-gcf-of.html' title='What Is The Greatest Common Factor (GCF) Of 60 And 72?'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=116155934505940188' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/116155934505940188'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/116155934505940188'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-115907891978327921</id><published>2006-09-24T16:08:00.000+10:00</published><updated>2006-11-09T12:28:20.685+11:00</updated><title type='text'>How Do I Find The Next Number In This Pattern?</title><summary type='text'>
I have been given the number pattern 98, 72, 77, 49, 54, 20... How do I find the next two numbers?

First, let's look at the differences between the numbers in this pattern.

For example, if you subtract the second number (72) from the first number (98), you will get 26.

(First Term) - (Second Term) = 98 - 72 = 26
(Second Term) - (Third Term) = 72 - 77 = -5
(Third Term) - (Forth Term) = 77 - 49</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/09/how-do-i-find-next-number-in-this.html' title='How Do I Find The Next Number In This Pattern?'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=115907891978327921' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115907891978327921'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115907891978327921'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-115898175787978332</id><published>2006-09-23T13:18:00.000+10:00</published><updated>2006-12-21T21:39:18.720+11:00</updated><title type='text'>How Do I Expand The Brackets And Find y?</title><summary type='text'>
If 7(y - 5) = 21, how do I expand the brackets so that I can find the value of y?

This equation has a single term outside the brackets. This term is highlighted in green.

7(y - 5) = 21

When an equation has a single term outside the brackets, we must multiply each term inside the brackets by the term outside the brackets.



In our example, that means that we must multiply the y by 7 and the -</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/09/how-do-i-expand-brackets-and-find-y.html' title='How Do I Expand The Brackets And Find y?'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=115898175787978332' title='2 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115898175787978332'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115898175787978332'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-115768090126251389</id><published>2006-09-08T11:56:00.000+10:00</published><updated>2006-11-09T12:28:20.548+11:00</updated><title type='text'>Probability Problem</title><summary type='text'>
A breakfast cereal company is running a competition: 2 in every 8 cereal boxes contain a prize. Emily bought a box of their rice pops and a box of their corn flakes. What is the probability that she won at least 1 prize?

We need to know the probability of Emily winning 1 or 2 prizes. An easy way to do this is to calculate the probability of her not winning a prize and subtracting this amount </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/09/probability-problem.html' title='Probability Problem'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=115768090126251389' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115768090126251389'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115768090126251389'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-115630339821595602</id><published>2006-08-23T13:19:00.000+10:00</published><updated>2006-11-09T12:28:20.492+11:00</updated><title type='text'>If 5x + 12 = 2x + 21, How Do I Find x?</title><summary type='text'>
We are trying to find out what number the letter x represents.

First, get all of the x's on one side of the equals sign (either the right or left side, it doesn't matter which).

For this equation, we will subtract 2x from both sides. Then we will have x's on the left side only. You must subtract the 2x from both sides of the equation, otherwise the sides will no longer be equal.

5x + 12 - 2x </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/08/if-5x-12-2x-21-how-do-i-find-x.html' title='If 5x + 12 = 2x + 21, How Do I Find x?'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=115630339821595602' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115630339821595602'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115630339821595602'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-115468201600085299</id><published>2006-08-04T18:45:00.000+10:00</published><updated>2006-11-09T12:28:20.432+11:00</updated><title type='text'>Online Maths and Science Tutoring Service</title><summary type='text'>
We offer an online maths and science tutoring service for Year 6 - 9 students. We communicate with our students using Skype (voice) and Windows Live Messenger (virtual whiteboard that both student and tutor can draw on and view in real time).

Students will need access to a computer with a broadband internet connection, microphone and speakers.

Cost: $25/hour, payable via PayPal or credit card.</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/08/online-maths-and-science-tutoring.html' title='Online Maths and Science Tutoring Service'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=115468201600085299' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115468201600085299'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115468201600085299'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-115002657424039422</id><published>2006-06-11T21:47:00.000+10:00</published><updated>2006-11-09T12:28:20.368+11:00</updated><title type='text'>Calculating Percentages</title><summary type='text'>
How do I convert '46 out of 368' to a percentage?

Step 1. Convert to a Fraction 
46 out of 368 is the same as 46/368. 

Step 2. Convert your Fraction into a Percentage 
To convert a fraction into a percentage, multiply the fraction by 100%.

For our example question:

46/368 x 100%

= (46 x 100%)/368

= 4600%/368

(divide 4600 by 368 to simplify)

= 12.5%

So, 46 out of 368 is the same as 12.5%</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/06/calculating-percentages.html' title='Calculating Percentages'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=115002657424039422' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115002657424039422'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/115002657424039422'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114860457070899744</id><published>2006-05-26T10:37:00.000+10:00</published><updated>2006-11-09T12:28:20.286+11:00</updated><title type='text'>Order Of Operations</title><summary type='text'>
1. Brackets
All possible actions within brackets should be done first. If there are brackets within brackets, work from the inside brackets out. (Brackets are also known as parentheses.)

2. Exponents
Next, simplify exponents (working from left to right). For example, if the expression contains 32, change it to a 9.

3. Multiplication &amp; Division
Then comes multiplication and division. If there </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/05/order-of-operations.html' title='Order Of Operations'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114860457070899744' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114860457070899744'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114860457070899744'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114794171954918208</id><published>2006-05-18T18:38:00.000+10:00</published><updated>2006-11-09T12:28:20.220+11:00</updated><title type='text'>What Is A Prime Number? What Is A Composite Number?</title><summary type='text'>
A prime number is a positive, whole number that has exactly two factors, 1 and itself. For example, 29 is a prime number because it has only two factors: 1 and 29.

A composite number has more factors than just 1 and itself. For example, 14 is a composite number because it has more than two factors. The factors of 14 are 1, 2, 7 and 14.

If you are trying to express a number as a product of its </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/05/what-is-prime-number-what-is-composite.html' title='What Is A Prime Number? What Is A Composite Number?'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114794171954918208' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114794171954918208'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114794171954918208'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114499221106494081</id><published>2006-04-14T15:17:00.000+10:00</published><updated>2006-11-09T12:28:20.158+11:00</updated><title type='text'>How Do I Solve 3x + 20 = 68</title><summary type='text'>
We want to find what x equals. To do this, we will try to get the equation in the form x = (some number).

Our starting equation is 3x + 20 = 68.

We are trying to get x by itself on one side of the equation. Therefore, it would be good to get rid of the 20 on the left hand side of the equation. So, we will subtract 20 from both sides of the equation.

Remember, whatever you do to one side of </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/04/how-do-i-solve-3x-20-68.html' title='How Do I Solve 3x + 20 = 68'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114499221106494081' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114499221106494081'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114499221106494081'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114438957212098933</id><published>2006-04-07T15:55:00.000+10:00</published><updated>2006-11-09T12:28:20.100+11:00</updated><title type='text'>I Need Help Understanding Percentages</title><summary type='text'>
Hope this movie helps. You should be able to pause the movie if you need to stop and think, or if it goes too fast for you to read. Please let me know if it doesn't work on your computer.</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/04/i-need-help-understanding-_114438957212098933.html' title='I Need Help Understanding Percentages'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114438957212098933' title='5 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114438957212098933'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114438957212098933'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114422574422582313</id><published>2006-04-05T18:27:00.000+10:00</published><updated>2006-11-09T12:28:19.853+11:00</updated><title type='text'>Algebra Problem</title><summary type='text'>
Question
Joe has a blue rope and a green rope; both ropes are the same length. He cuts the blue rope into 5 pieces of equal length. He cuts the green rope into 12 pieces of equal length.

Each piece of blue rope is 119cm longer than each piece of green rope.

How long was the blue rope before it was cut into pieces?

Answer
We are trying to find the original length of the blue rope, this is the </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/04/algebra-problem.html' title='Algebra Problem'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114422574422582313' title='6 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114422574422582313'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114422574422582313'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114377334609208856</id><published>2006-03-31T13:33:00.000+11:00</published><updated>2006-12-21T21:24:03.552+11:00</updated><title type='text'>Index Laws (Part 1)</title><summary type='text'></summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/03/index-laws-part-1.html' title='Index Laws (Part 1)'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114377334609208856' title='2 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114377334609208856'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114377334609208856'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114362777618379600</id><published>2006-03-29T21:20:00.000+11:00</published><updated>2006-12-21T21:21:29.520+11:00</updated><title type='text'>Number Patterns (Part 2)</title><summary type='text'>
If none of the strategies in Number Patterns Part 1 work for your number pattern, you can try using a table like the one below (click on the table to see a larger view).



Our example number pattern will be: 4, 7, 12, 19, 28, … 
Put the numbers in your number pattern into Row A of the table (click the table to see a larger view). 


Then, figure out what you could do to the first number in your</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/03/number-patterns-part-2_29.html' title='Number Patterns (Part 2)'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114362777618379600' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114362777618379600'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114362777618379600'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114327610270056424</id><published>2006-03-25T19:36:00.000+11:00</published><updated>2006-11-09T12:28:19.547+11:00</updated><title type='text'>Finding The Next Term In A Number Pattern</title><summary type='text'>
Ask yourself: Do the numbers in this number pattern increase in value (go up) or decrease in value (go down)?

If the numbers increase, do they increase by the same amount each time?
If the numbers decrease, do they decrease by the same amount each time?

Example 1

In the example below, the numbers are increasing.

1, 13, 25, 37, 49, …

What do you need to add to each number to get to the next </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/03/finding-next-term-in-number-pattern.html' title='Finding The Next Term In A Number Pattern'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114327610270056424' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114327610270056424'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114327610270056424'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114315668165012578</id><published>2006-03-24T10:14:00.000+11:00</published><updated>2006-12-21T21:12:37.243+11:00</updated><title type='text'>Equivalent Fractions</title><summary type='text'>
If we multiply both the numerator and the denominator of a fraction by the same number, then we are not changing the value of the fraction. We are only changing the form that the fraction is in.

For example, if we multiply 1/2 by 2/2, we get 2/4.

2/4 is still the same amount as 1/2. This is illustrated in the picture below.



Say we want to convert 2/3 to an equivalent fraction with a </summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/03/equivalent-fractions.html' title='Equivalent Fractions'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114315668165012578' title='1 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114315668165012578'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114315668165012578'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114310424808706070</id><published>2006-03-23T19:55:00.000+11:00</published><updated>2006-11-09T12:28:19.430+11:00</updated><title type='text'>Free Maths Worksheets</title><summary type='text'>
We are beginning to add free maths worksheets to our website (see column at left). If you have any questions about these worksheets, please ask us (email: help@onlinetutor.com.au)!</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/03/free-maths-worksheets.html' title='Free Maths Worksheets'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114310424808706070' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114310424808706070'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114310424808706070'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114255304519074426</id><published>2006-03-17T10:33:00.000+11:00</published><updated>2006-12-21T21:09:52.628+11:00</updated><title type='text'>Fraction Problem</title><summary type='text'>
Question

How would I solve: 2 1/6 + 3(4 5/12 + 1/6) ?


Answer

First, do the addition inside the brackets. Converting 4 5/12 to an improper fraction might make this easier. 4 5/12 is equivalent to 53/12.

So our question can now be written: 2 1/6 + 3(53/12 + 1/6).

Now, when adding fractions (for some help with adding fractions click here) the denominators of the fractions need to be the same.</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/03/fraction-problem.html' title='Fraction Problem'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114255304519074426' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114255304519074426'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114255304519074426'/><author><name>Amanda &amp; Debbie</name></author></entry><entry><id>tag:blogger.com,1999:blog-23073148.post-114178374109854047</id><published>2006-03-08T12:52:00.000+11:00</published><updated>2006-11-21T13:36:21.216+11:00</updated><title type='text'>How To Add Fractions</title><summary type='text'>
If the fractions you are trying to add have the same denominator, you can simply add the numerators, keeping the denominator the same.

For example, to solve 1/7 + 3/7

Add the numerators: 1 + 3 = 4

The denominator stays the same.

The answer is 4/7.

If the fractions you are trying to add have different denominators you need to convert the fractions so that all the denominators are the same.

</summary><link rel='alternate' type='text/html' href='http://www.onlinetutor.com.au/2006/03/how-to-add-fractions.html' title='How To Add Fractions'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=23073148&amp;postID=114178374109854047' title='0 Comments'/><link rel='replies' type='application/atom+xml' href='http://www.onlinetutor.com.au/atom.xml' title='Post Comments'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114178374109854047'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/23073148/posts/default/114178374109854047'/><author><name>Amanda &amp; Debbie</name></author></entry></feed>